Databinding with DataGridView in ADO.NET C#

DataGridView is very powerful and flexible control for displaying records in a tabular (row-column) form. Here I am describing a different way of databinding with a DataGridView control.

Take a windows Form Application -> take a DataGridView control.

Follow the given steps.

Step 1 :
 Select DataGridView control and click at smart property. Look at the following figure.

Step 2 : After clicking, a pop-up window will be open.

Step 3 : Click ComboBox.

Step 4 : Click at Add Project Data Source (Look at above figure). A new window will be opened to choose Data Source Type.

Step 5 : Choose Database (By default it is selected) and click the next button. A new window will be open to Database Model.

Step 6 : Select DataSet (By default it is selected) and click the next button. A new window will be open.

Step 7 : Click at New Connection button.

Step 8 : Write Server name, User name and Password of your SQL server and select Database name. Look at the following figure.

Step 9 : Click “ok” button. After clicking ok button, you will reach the Data Source Configuration Wizard.

Step 10 : Click the next button.

 

Step 12 : Click on Table to explore all tables of your Database.

Step 13 : Click on the selected Database table to explore all columns.

Step 14 : Check the CheckBox to select columns.

Step 15 : Click the Finish button. You will note that the DataGridView will show all columns of the table (Here, “Student_detail”).

Run the application.

Output

Now we bind the DataGridView with database by code. Take another DataGridView control and write the following code on the form load event.

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Data.SqlClient;

namespace DatabindingWithdataGridView
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
SqlDataAdapter dadapter;
DataSet dset;
string connstring = “server=.;database=student;user=sa;password=wintellect”;
private void Form1_Load(object sender, EventArgs e)
{
dadapter = new SqlDataAdapter(“select * from student_detail”, connstring);
dset = new System.Data.DataSet();
dadapter.Fill(dset);
 dataGridView1.DataSource = dset.Tables[0].DefaultView;
}
}
}

Run the application. Output will be same as above.

Here are some related resources

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